How Many Different 5-digit Zip Codes Are There If No Digit Is Repeated?

Question

How Many Different 5-digit Zip Codes Are There If No Digit Is Repeated?

4 Answers

Answer Question

Answer 1

There are 10 digits in total (1,2,3,4,5,6,7,8,9,0).
The formula is P(n,r) = n!/(n-r)!
P (10, 5) = 10!/(10-5)!
= 10!/5!
= 10 x 9 x 8 x 7 x6 = 30240

Hope this helps !!!!

Answer 2

Anonymous answered

It's 100,000
you multiply 10 by it's self 5 times

Answer 3

I think you have 9 possibilities for the first digit, 8 for the second, 7 for third, 6 for the fourth, and 5 for the fifth. ( assuming zero is not a possibility). The number of 5-digit non-repeating might be 9x8x7x6x5=15120.

Answer 4

The above question is definitely from the Permutations theory. Permutation refers to the rearrangement of numbers into distinguishable sequences. The formula for permutation is
P(n,r)= n!/(n-r)!
According to the above information the values for the formula will be:
P(5,5)=5!/(5-5)!
P=5!
P=5x4x3x2x1= 120
Thus there are 120 different 5 digit zip codes if the digits 1...5 are used and no digit is repeated.